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2. An orbit of a satellite around a planet is an ellipse, with the planet at one focus of this ellipse. The distance of the satellite from this star varies from 300, 000 km to 500, 000 km, attained when the satellite is at each of the two vertices. Find the equation of this ellipse, if its center is at the origin, and the vertices are on the x-axis. Assume all units are in 100, 000 km.​

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Leyzeramlago

Answer:

x²/16 + y²/15=1

Step-by-step explanation:

for this question, we are going to write the equation of an ellipse that represents the elliptical orbit of a planet of a satellite around a star. We are told that the origin is the center, so that determines my enumerators And the equation of the lips is always equal to one. Right now. The distance of the star or satellite rather from the star stars at the origin is elliptical and we are told that the vertex is are on the X axis. So the farthest distance is verdict horizontally. That's 500,000 500,000. Each unit is 100,000 and the smallest distance From the start to the satellite is three 100,000. So we will take the five which is in 100 thousands and put five squared below the X. We will take three representing 300,000 and three squared is nine below the Y. Here is the equation of the elliptical orbit.

x²/16 + y²/15=1

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