Sagot :
Step-by-step explanation:
[tex] {x}^{2} + 6x > - 16 \\ {x}^{2} + 6x + 16 > 0 \\ {x}^{2} + 6x + 16 = 0 \\ {x}^{2} + 6x + 16 > 0 \: \: \: \: \: a = 1[/tex]
Step-by-step explanation:
[tex] {x}^{2} + 6x > - 16 \\ {x}^{2} + 6x + 16 > 0 \\ {x}^{2} + 6x + 16 = 0 \\ {x}^{2} + 6x + 16 > 0 \: \: \: \: \: a = 1[/tex]