Sagot :
✏️IDEAL GAS EQUATION
[tex]\tt{\huge{\green{Solution:}}}[/tex]
The problem asks to solve for the pressure of the gas inside the tank. First, we need to identify the quantities to be used. These are
P = pressure
V = volume
n = number of moles
R = universal gas constant = 0.082057 L • atm/K • mol
T = absolute temperature
m = mass
MW = molecular weight
Second, we need to identify the given values. These are
V = 25.0 L
T = 25°C + 273.15 = 298.15 K
m = 11.0 kg = 1.10 × 10⁴ g
Third, we need to find the molecular weight of gas. Since the given gas is butane, the molecular weight is
MW = (12.01 g/mol × 4) + (1.008 g/mol × 10)
MW = 58.12 g/mol
Fourth, we need to find the number of moles of gas. The number of moles of butane gas is
[tex]n = \dfrac{m}{\text{MW}}[/tex]
[tex]n = \dfrac{1.10 \times 10^{4} \: \text{g}}{\text{58.12 g/mol}}[/tex]
n = 189.26 mol
Finally, we can now solve for the pressure of the gas. Therefore, the pressure of the gas is
[tex]P = \dfrac{nRT}{V}[/tex]
[tex]P = \dfrac{(\text{189.26 mol})(0.082057 \: \text{L} \: \cdot \: \text{atm/}\text{K} \: \cdot \: \text{mol})(\text{298.15 K})}{\text{25.0 L}}[/tex]
[tex]\boxed{P = \text{185 atm}}[/tex]
[tex]\\[/tex]
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