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The sum of the first is 11 terms of 1/2 -1/2, 1/2 -1/2.

Sagot :

[tex]\colorbox{red}G\colorbox{blue}E\colorbox{pink}O\colorbox{green}M\colorbox{purple}E\colorbox{orange}T\colorbox{blue}R\colorbox{pink}I\colorbox{green}C[/tex]

[tex]\colorbox{purple}S\colorbox{orange}E\colorbox{red}R\colorbox{blue}I\colorbox{yellow}E\colorbox{green}S[/tex]

FORMULA:

[tex] s_{n} = \frac{ a_{1}( {r}^{n} - 1) }{r - 1} [/tex]

SOLUTION:

[tex] s_{11} = \frac{ \frac{1}{2} ( { - 1}^{11} - 1) }{ - 1 - 1} = \frac{ \frac{1}{2}( - 2) }{ - 2} = \frac{1}{2} [/tex]

ANSWER:

Therefore, the sum of the first 11 terms is

[tex]\huge\pink{\boxed{\frac{1}{2}}} [/tex]