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The grade of Sheryl for the first three gradings are 75 78 and 81. What must be her grade in the 4th grading to get an average of 80?


Sagot :

Answer:

83,81,82

Step-by-step explanation:

if it's wrong plsss correct me

The grade of Sheryl for the first three gradings are 75 78 and 81. What must be her grade in the 4th grading to get an average of 80?

 

Answer: 167

 

Step-by-step explanation:

Required Average  =  80

Let the required grade be  x.

[tex]Average=\frac{sum\:of\:n}{n} \\\\ 80=\frac{75+78+81+x}{4}\\ 320=153+x\\x=320-153\\{ \boxed{ \boxed{ \tt \blue{=167}}}}[/tex]

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