Sagot :
Answer:
Hey!
[tex]\begin{cases}x = 1 \\ y = 3 \end{cases}[/tex] or [tex] \begin{cases}x = 1 \\ y = - 3 \end{cases}[/tex] or [tex] \begin{cases}x = - 1 \\ y = 3 \end{cases}[/tex] or [tex] \begin{cases} x= - 1 \\ y = - 3 \end{cases}[/tex]
Step-by-step explanation:
[tex]\begin{cases} {4x}^{2} + {y}^{2} = 13 \\ {x}^{2} + {y}^{2} = 10 \end{cases}[/tex]
- Rearrange like terms to the same side of the equation
- [tex] \begin{cases} {y}^{2} = 13 - {4x}^{2} \\ {x}^{2} + {y}^{2} = 10\end{cases}[/tex]
- Substitute into one of the equations
- [tex] {x}^{2} + 13 - {4x}^{2} = 10[/tex]
- Rearrange all nonzero terms to the left side of the equation
- [tex] {x}^{2} + 13 - {4x}^{2} - 10 = 0[/tex]
- Combine like terms
- [tex] { - 3x}^{2} + 3 = 0[/tex]
- Reduce the greatest common factor on both sides of the equation
- [tex] { - x}^{2} + 1 = 0[/tex]
- Rearrange unknown terms to the left side of the equation
- [tex] { - x}^{2} = - 1[/tex]
- Divide both sides of the equation by the coefficient of the variable
- [tex] {x}^{2} = 1[/tex]
- Split into two equations
- [tex]x = ± \sqrt{1} [/tex]
- Combine the results
- [tex]x = 1, \: x = - 1[/tex]
[tex] \begin{cases} {x}^{2} + {y}^{2} = 10 \\ x = 1 \end{cases}[/tex]
- Substitute into one of the equations
- [tex] {1}^{2} + {y}^{2} = 10[/tex]
- Calculate the power
- [tex]1 + {y}^{2} = 10[/tex]
- Rearrange all nonzero terms to the left side of the equation
- [tex]1 + {y}^{2} - 10 = 0[/tex]
- Combine like terms
- [tex] - 9 + {y}^{2} = 0[/tex]
- Rearrange unknown terms to the left side of the equation
- [tex] {y}^{2} = 9[/tex]
- Split into two equations
- [tex]y = ± \sqrt{9} [/tex]
- Combine the results
- [tex]y=3[/tex] or [tex] y=-3[/tex]
Same process for the [tex] \begin{cases} {x}^{2} + {y}^{2} = 10 \\ x = - 1 \end{cases} [/tex]
Therefore the solution of the system is
- (y = 3 or y = -3)
- [tex]\begin{cases}x = 1 \\ y = 3 \end{cases}[/tex] or [tex] \begin{cases}x = 1 \\ y = - 3 \end{cases}[/tex] or [tex] \begin{cases}x = - 1 \\ y = 3 \end{cases}[/tex] or [tex] \begin{cases} x= - 1 \\ y = - 3 \end{cases}[/tex]
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