Sagot :
Answer:
1. 36
2. -4(m + 4)
3. di q po alm
4. y³×(y²+1)
5. m×(m⁶+n)
Step-by-step explanation:
Sorry hindi ko po alam ung num 4
Answer:
[tex]1.) \: 2x + 18 \\ \\ solution. \: \\ 2x + 18 \\ 2x + 2⋅3 {}^{2} \\ 2(\frac{2x}{2} + \frac{2⋅3 {}^{2} }{2} ) \\ 2(x + 3 {}^{2} ) \\ 2(x + 9)[/tex]
[tex]2.) \: - 4m - 16 \\ \\ solution. \\ - 4m - 16 \\ - 2 {}^{2} ⋅m - 2 {}^{4} \\ 2 {}^{2} ( - \frac{2 {}^{2}⋅m}{2 {}^{2} } - \frac{2 {}^{4} }{2 {}^{2} }) \\ 4( - m - (2 {}^{4 - 2} )) \\ 4( - m - (2 {}^{2} )) \\ 4( - m - 4)[/tex]
[tex]3.) \: 3x {}^{3} - 12x {}^{2} - 9x \\ \\ solution. \\ 3x {}^{3} - 12x {}^{2} - 9x \\ - 9x {}^{3} - 9x \\ - 3 {}^{2} ⋅x {}^{3} - 3 {}^{2} ⋅x \\ 3 {}^{2} ⋅x( - \frac{3 {}^{2}⋅x {}^{3} }{3 {}^{2}⋅x {}^{} } - \frac{3 {}^{2}⋅x}{3 {}^{2}⋅x} ) \\ 9x( - (x {}^{3 - 1} ) - 1) \\ 9x( - (x {}^{2}) - 1) [/tex]
[tex]4.) \: y {}^{5} + y {}^{3} \\ \\ solution. \\ y {}^{5} + y {}^{3} \\ y {}^{3} ( \frac{y {}^{5} }{y {}^{3} } + \frac{y {}^{3} }{y {}^{3} } ) \\ y {}^{3} (y {}^{5 - 3} + 1) \\ y {}^{3} (y {}^{2} + 1)[/tex]
[tex]5.) \: m {}^{5} n {}^{2} + mn \\ \\ solution. \\ m {}^{5} n {}^{2} + mn \\ mn( \frac{m {}^{5}n {}^{2} }{mn} + \frac{mn}{mn}) \\ mn(m {}^{5 - 1} n {}^{2 - 1} + 1) \\ mn(m {}^{4} n + 1)[/tex]
Step-by-step explanation:
Hope it helps!