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Problem: The height () of the ball thrown into the air with an initial velocity of 9.8 / from

a height of 2 above the ground is given by the equation () = −4.9

2 + 9.8 + 2, where

is the time in seconds that the ball has been in the air.​

Problem The Height Of The Ball Thrown Into The Air With An Initial Velocity Of 98 From A Height Of 2 Above The Ground Is Given By The Equation 492 98 2 Where Is class=

Sagot :

Aljoncentillas43go

Answer:

wala ako dyan absent ajo dyan sorry

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