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what is the sum of the first 12 terms of the geometric series who first terms in 14 and common ratio is 2​

Sagot :

Answer:

57330

Step-by-step explanation:

To get the sum, we can use the formula:

Sₙ = [a₁(1 - rⁿ)]/(1 - r)

where:

Sₙ = the sum of the first n terms

a₁ = the first term

n = the number of terms

r = the common ratio, r ≠ 1

In the problem, the given values are:

a₁ = 14

n = 12

r = 2

Substitute these values to the formula above.

Sₙ = [a₁(1 - rⁿ)]/(1 - r)

S₁₂ = [14(1 - 2¹²)]/(1 - 2)

S₁₂ = [14(1 - 4096)]/(-1)

S₁₂ = [(14)(-4095)/(-1)

S₁₂ = (-57330)/(-1)

S₁₂ = 57330

The sum of the first 12 terms of the geometric series is 57330.