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find four consecutive even integers has the product of the first second and fourth is 1920

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Sagot :

Julianokerviego

Answer:

10 12 14 16

Step-by-step explanation:

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Kyfaulyxgo

Answer:

assuming the four consecutive even integers is

x (x+2) (×+4) (x+6)

so. x•(x+2)(x+6) = 1920

---> x(x^2+8x+21) = 1920

x^3+8^2+12x-1920 = 0

x = 10 {X is integer}

so. x+2 = 12

x+4 = 14

x+6 = 16

the four consecutive even integers are 10 12 14 and 16

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