The answer is
[tex]2x {}^{2} - x + 1[/tex]
Solution:
[tex](6 {}^{3} - 5x {}^{2} + 4x - 1) \div (3x - 1) \\ \frac{6x {}^{3} - 2x {}^{2} - 3x {}^{2} + x + 3x - 1 }{3x - 1} \\ \frac{2x { }^{2} \times (3 - 1) - x \times (3x - 1) + 1(3x - 1) }{3x - 1}\\\frac{(3 \times - 1) \times(2x {}^{2} - x + 1)}{3x - 1} \\ = 2x {}^{2} - x + 1[/tex]
