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2. f(x) = x3 - 6x2 + 12x - 8 r=2​

Sagot :

Answer:

f(x)=x3=6x2+12x−8

f(x)=3(x2−4x+4)

f(x)=3(x−2)2

f(x)=0 ⇒ x=2

But clearly f(x) does not change sigh about x=2. f(2)<0 and f(2)<0.So f(x) has no point of maxima or minima . In fact f(x) is a monotonically increasing function for x∈R

Step-by-step explanation:

f(2) = 2(3)-6(2)2+12(2)-8
=6-24+24-8
= -18+16
= -2