Answer:
We need to prepare 300 ml of a ferric sulfate solution for fertilizing plants with a 12 g/L mass
concentration. How much ferric sulfate mass do we need?
(result: 3,6 g of ferric sulfate)
solute ferric sulfate
solvent water
solution 300 ml of fertilizing solution with 12g/l ferric sulfate
mass concentration= mass of solute
volume of solution
Units change: Volume in ml must be changed to liter
300ml∗
1l
1000ml =0,30 l
Mass of solule calculation
mass concentration= x g
0,30l
=12 g /l of ferric sulfate
x g=12(
g
l )
∗0,30 (l)=3,6 g of ferric sulfate
We need 3,6 g of ferric sulfate.
