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If n-m is even, then n²-m² is also even

Sagot :

[tex]{\boxed{\color{red}\tt{Answer:}}}[/tex]

If we’ve provided this number by 2

  • (n-m)²
  • 2(-m²+nm)

it can determine an divisible number 2

So, We can take the factor by number 2 in the whole expression of even

  • And Last, The n²- m² is always/also even.

[tex]#TheTrio's(Deashi)[/tex]

  • [tex]{\boxed{\color{purple}\tt{SYX}}}[/tex]

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