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Aljoncastrodelacruzgo
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B Let's Try Solve the problem. Use the same answer sheet. Show your complete solution. (5pts each) Problem #1. Calculate the mass percent of Benzene and Carbon tetrachloride if 22 g of benzene is dissolved in 122 g of carbon tetrachloride. Percent by mass= mass of solute + mass of solvent x 100 % mass of solution < Problem #2. Rubbing alcohol is sold as 70% (v/v) solution of isopropyl alcohol in water. What volume of isopropyl alcohol is used to make 500 mL of rubbing alcohol? (Use the equation (m/v) x 100%) Problem #3. What is the percent by volume of ethanol in final solution when 85 mL of ethanol is diluted to a volume of 250 mL with water? a (Use the equation (m/v) x 100%) Problem #4. A pharmacist adds 2.00 mL of distilled water to 4.00g of powdered drug. The final volume of the solution is 3.00mL. What is the concentration of the drug in g/100mL of solution? what is the percent (m/v) of the solution?​

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Answer:

Given that,

Mass of benzene  = 22 g

Mass of carbon tetrachloride  = 122 g

Mass of solution dissolved = 22 g + 122 g = 144 g

Then, we have to find,

Mass percentage of benzene = ?

Mass percentage of carbon tetrachloride = ?

Now, using the formula,

∴ Mass percentage of benzene =  × 100

⇒ Mass percentage of benzene =  × 100

⇒  × 100

⇒  × 100

⇒  = 15.2%

→ Mass percentage of benzene = 15.2%

∴ Mass percentage of  = 100 -15.2% = 84.8%

→ Mass percentage of  = 84.8%

Explanation:

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