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what are the roots of x(x+1)(x-3)(2x-1)=0?
show solutions pls thanks​


Sagot :

✨Answer✨

[tex] x = 0 \: or \: x = - 1 \: or \: x = 3 \: or \: x = \frac{1}{2} [/tex]

✍️EXPLANATION OF THIS ANSWER✍️

[tex]x( x \: + 1)(x - 3)(2x - 1) = 0[/tex]

APPLY ZERO PRODUCT PROPERTY↓

[tex] \times = 0 \: or \: x + 1 = 0 \: or \: x - 3 = 0 \: or \: 2x - 1 = 0[/tex]

SOLVING STEPS⭐

[tex] log(x + 1 = 0) or \: x - 3 = 0 \: or \: 2x - 1 = 0[/tex]

x+1=0↓

Rearrange unknown terms to the left side of the equation:

x=-1

OR

x-3=0

Rearrange unknown terms to the left side of the equation:

x = 3

OR

2x-1=0

Rearrange unknown terms to the left side of the equation:

2x=1

Divide both sides of the equation by the coefficient of variable:

[tex]x = \frac{1}{2} [/tex]

[tex]x = 0 \: or \: x = - 1 \: or \: x = 3 \: or \: x = \frac{1}{2} [/tex]

Combine the results

[tex]x = 0 \: or \: x = - 1 \: or \: x = 3 \: or \: x = \frac{1}{2} [/tex]

Final Answer

[tex]x = 0 \: or \: x = - 1 \: or \: x = 3 \: or \: x = \frac{1}{2} [/tex]

#CARRY ON LEARNING