Explanation:
QUESTION:
If the roots are -2, -3, 4, 6 how do you express that as linear factors? Show solution.
A. (x-2)(x-3)(x+4)(x+6)=0
B. (x+2)(x+3)(x-4)(c-6)=0
C. (x-2)(x+3)(x-4)(x+6)=0
D. (x+2)(x-3)(x+4)(x-6)=0
\begin{gathered} \\ \end{gathered}
\large{\mathcal{SOLUTION:}}SOLUTION:
Given the roots: -2 , -3 , 4 , 6
Equate the roots to 0
For -2
x = -2
x+2 = 0
For -3
x = -3
x+3 = 0
For 4
x = 4
x-4 = 0
For 6
x = 6
x-6 = 0
\begin{gathered} \\ \end{gathered}
Therefore , (x+2)(x+3)(x-4)(x-6) are the linear factors.
\begin{gathered} \\ \end{gathered}
\large{\mathcal{ANSWER:}}ANSWER:
LETTER B (x+2)(x+3)(x-4)(x-6)
