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what is the speed of sound along Roxas Boulevard in Manila in the summer when the temperature is 32°C? Compare this with the speed of sound in December when the temperature is 19°C.

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Sagot :

✏️ Sound

[tex] {\Large{\overline{\underline{\sf{\hookrightarrow Answer:}}}}} [/tex]

  • » The speed of sound along Roxas Boulevard in Manila in the summer which is 350.2 m/s, is faster than the speed of sound in the same area in the winter, which is 342.4 m/s. This explains that the speed of sound is affected by the temperature of the medium. The hotter the medium, the faster the sound travels.

Solution:

Here, we use the formula for the speed of sound in air at a given temperature.

[tex] {\large{\boxed{\sf{V = 331 \frac{m}{s} + 0.6 \frac{\frac{m}{s}}{°C} (T) }}}} [/tex]

Solve first for the speed of sound along Roxas Boulevard in Manila in the summer, where [tex] \sf T [/tex] = 32 °C.

  • [tex] \sf{V = 331 \frac{m}{s} + 0.6 \frac{\frac{m}{s}}{°C} (32 °C) } [/tex]
  • [tex] \sf{V = 331 \frac{m}{s} + 19.2 {\frac{m}{s}} } [/tex]
  • [tex] {\sf \therefore V = {\boxed{\green{\sf{350.2 \frac{m}{s}}}}}} [/tex]

Now solve for the speed of sound in the same area in the winter, where [tex] \sf T [/tex] = 19 °C.

  • [tex] \sf{V = 331 \frac{m}{s} + 0.6 \frac{\frac{m}{s}}{°C} (19 °C) } [/tex]
  • [tex] \sf{V = 331 \frac{m}{s} + 11.4 {\frac{m}{s}} } [/tex]
  • [tex] {\sf \therefore V = {\boxed{\green{\sf{342.4 \frac{m}{s}}}}}} [/tex]

[tex]{\: \:}[/tex]

[tex] {\huge{\overline{\sf{Hope\:It\:Helps}}}} [/tex]

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