👤

mang juan owns a rectangular lot. the perimeter of the lot is 90 m and its area is 350 m2 what are the dimensions of the rectangular lot,pakisagot ng maayos pls with solution​

Sagot :

Answer:

L = 35

W = 10

Step-by-step explanation:

Let L be the length & W be the Width of rectangle.

Area = 350

350 = LW     eq.1

Perimeter = 90

90 = 2L + 2W

L = (90 -2W)/2

substitute L to eq.1

350 = W(90-2W)/2

700 = 90W-2W^2

700 = 90[tex]W^{}[/tex] - 2[tex]W^{2}[/tex]

2[tex]W^{2}[/tex] - 90[tex]W^{}[/tex] + 700 = 0  

[tex]W^{2}[/tex] - 45W + 350

factoring the quadratic eq.      

(W - 35)  (W - 10 ) = 0  

W = 35 or W = 10

checking from Area.

A=LW

W = 10

350 = 10L

L = 35, ok