👤

A positively charged bead having a mass of 1.00 g falls from rest in a vacuum from a height of 5.00 m in a uniform vertical electric field with a magnitude of 1.00 x 104 N/C. The bead hits the ground at a speed of 21.0 m/s. Determine (a) the direction of the electric field (up or down), and (b) the charge on the bead.

Sagot :

Answer:

a) The direction of electric field is downward for the positively charged bead. We consider the case only with gravitational force, without any electrostatic force. v^2 - u^2 = 2gs or, v^2 = 2x9.81x5 or, v = 9.9 m/s. But the given final speed of fall is 21m/s. This shows that the electrostatic and the gravitational force were acting in the same direction. So, electric field is downwards. b) acceleration due...

Explanation:

sana maka tulong pa brainleist answer po ty