Answer:
[tex] \frac{x - 8}{3} - \frac{10x}{3} \\ = \frac{x - 8 - 10x}{3} \\ = \frac{ - 9x - 8}{3} \\ = - \frac{9x - 8}{3} [/tex]
[tex] \frac{8x + 3}{x + 1} + \frac{x + 2}{x - 1} \\ = \frac{(x + 1) \times (8x + 3) + (x + 1) \times (x + 2}{(x + 1) \times (x - 1)} \\ = \frac{8x {}^{2} + 3x - 8x - 3 + x {}^{2} + 2x + x + 2}{x {}^{2} - 1 } \\ = \frac{9x {}^{2} - 2x - 1}{x {}^{2} - 1 } [/tex]
Step-by-step explanation:
Hope it help.
