Sagot :
Answer:
The percent by mass of NaHCO3 is 3.23%.
Explanation:
Given: mass of solute = 20g
mass of solvent = 600g
Find: Percent by mass of solute
Solution:
mass of solution = 20g + 600g = 620g
[tex]\% = \frac{mass \: ofsolute}{mass \: of \: solution} \times 100 \\ \% = \frac{20g}{620g} \times 100 \\ \% = {0.0323} \times 100 \\ \% = 3.23[/tex]
Answer:
#"Approx. 3%"#
Explanation:
We simply work out the quotient:
#"Mass of sodium bicarbonate"/"Mass of sodium bicarbonate solution"xx100%=#
#(20*g)/(20*g+600*g)xx100%=3.2%(m/m)#.