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which of the following is the principal root of ³√125​

Sagot :

Answer:

5

Step-by-step explanation:

125=5x25

∴∛125=∛5x5x5

         =(5x5x5)[tex]1/3[/tex]=(5³)

         =(5)³×[tex]1/3[/tex] using (a^m)ⁿ=a^mˣⁿ

         =(5)¹ = 5 ←  ans.

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