👤

F=ma
a=F/m
m=F/a
1. If an object has an acceleration of 5m/s² and a mass of 10kg, how much force was applied?
2. A 20kg sugar was moved from left to right side of the canteen with a total force of 30N, what is the
acceleration of the object?
3. A cart at rest was pushed with a 50 N force and is traveling at 30m/s? down the slope. What is the mass of
the object?​


Sagot :

Answer:

1. F = 50N

2. a = 1.5m/[tex]s^{2}[/tex]

3. m = 1.67 kg

Explanation:

1. a = 5m/[tex]s^{2}[/tex]

  m = 10 kg

  F = ?

[tex]F = ma\\F = (10kg)(5m/s^{2} )\\F = 50kgm/s^{2} \\F = 50N[/tex]

2. m = 20 kg

    F = 30N

    a = ?

[tex]a = \frac{F}{m} \\a = \frac{30N}{20kg} \\a = \frac{30kgm/s^{2} }{20kg} \\a= 1.5m/s^{2}[/tex]

3. F = 50N

   a = 30 m/s

   m = ?

[tex]m = \frac{F}{a} \\m = \frac{50N}{30m/s^{2} } \\m = \frac{50kgm/s^{2} }{30m/s^{2} } \\m = 1.67kg[/tex]