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determine the standard form of equation of a circle
1.x2+y2+4x+2y=4
2.x2=36-y2


Sagot :

Answer:

The equation is equavilent to:

(x^2-4x+4)+(y^2-2y+1)-9 = 0

(x-2)^2+(y-1)^2 = 9 = 3^2

This is a circle that is centered at (2,1) with radius 3

Step-by-step explanation:

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