Sagot :
a. !(x > 10)
x == 10, therefore !(10 > 10), which becomes !(false) which becomes true
Answer: true
b. x <= 5 || y < 15
x == 10 and y == 15, x <= 5 || y < 15 becomes 5 <= 5 || 15 < 15 which becomes true || false, which becomes true
Answer: true
c. (x != 5) && (y != z)
x == 10, y == 15 and z == 20, (x != 5) && (y != z) becomes (10 != 5) && (15 != 20), which becomes (true) && (true), which of course is true.
Answer: true
d. x >= z || (x + y >= z)
x == 10, y == 15 and z == 20, x >= z || (x + y >= z) becomes 10 >= 20 || (10 + 15 >= 20, which becomes false || (25 >= 20) which becomes false || true, which simplifies to true.
Answer: true
e. (x <= y - 2) && (y >= z) || (z - 2 != 20)
x == 10, y == 15 and z == 20, (x <= y - 2) && (y >= z) || (z - 2 != 20) becomes (10 <= 15 - 2) && (15 >= 20) || (20 - 2 != 20), which becomes (10 <= 13) && (false) || (18 != 20), which becomes (true) && (false) || (true), which becomes false || true, which becomes true.
Answer: true