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Assessment: Refer to your Module 5. Transform the equation to quadratic equation, and find the solutions of each by matching column A with column B. A Standard Form В. 1. x2 +2x = -1 A. X= 16V13 2 2. x2 + 2 = x +5 3. (x+2(x-1)=3 4.1+ 1 _ x2 x-4 x+4 x2-16 P. The QE has no real roots/ solutions E. x= 17 N.x=1 I. x = 0 and x =2 R. x= 1 and x=-3 1 5. x+1 X-2​

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Answer:

Assessment: Refer to your Module 5. Transform the equation to quadratic equation, and find the solutions of each by matching column A with column B. A Standard Form В. 1. x2 +2x = -1 A. X= 16V13 2 2. x2 + 2 = x +5 3. (x+2(x-1)=3 4.1+ 1 _ x2 x-4 x+4 x2-16 P. The QE has no real roots/ solutions E. x= 17 N.x=1 I. x = 0 and x =2 R. x= 1 and x=-3 1 5. x+1 X-2​

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