👤

The perimeter of a rectangle is 20 cm. Find the possible dimensions if the area of the rectangle must be less than78 cm2.​

Sagot :

(a,b) =(5,5), (4,6),(3,7),(2,8),(1,9),(6,4),(7,3),(8,2),(9,1)

Explanation:

Let's analyze. So perimeter of a rectangle is given by the formula:

P =2 ⋅ (a+b).

So,   2 ⋅ ( a + b ) =  20

And we are given that Area 21 c m  2  ⇒ a ⋅ b  <  21

Back to perimter   2 ⋅( a + b )  = 20  ⇒  a + b = 20  2  =  10

And we are given  a ⋅ b  <  21 ,  which gives us pairs  ( a , b )  = ( 5 , 5 ) , ( 4 , 6 ) , ( 3, 7 ) , ( 2 , 8 ) , ( 1, 9 ) , ( 6 , 4 ) , ( 7 ,3 ) ,( 8 , 2 ) , 9 , 1 )