Independent Assessment 2
Directions: Determine if d(x) is a factor of p(x).
1. p(x) = x
3 – 2x +1; d(x) = x -1
2. p(x) = 4x3 – x
2 – 6x +16; d(x) = x – 2
3. p(x) = x4 + 2x2 – 7x – 9 ; d(x) = x – 2
4. p(x) = 2x4 + 11x3 + 21x2 + 17x + 5; d(x) = x+1
5. p(x) = x5 – x
4 – 7x3 + 7x2
- 12x + 12; d(x) = x – 1


pa help po pls