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what is the energy of the photon of an x-ray with a frequency of 2x10^19 hz​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The energy of a photon is given by

[tex]\boxed{E = hf}[/tex]

where:

E = energy

h = Planck's constant = [tex]6.63 \times 10^{-34}[/tex] J • s

f = frequency

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the energy of the photon

E = hf

[tex]E = (6.63 \times 10^{-34} \: \text{J} \cdot \text{s})(2 \times 10^{19} \: \text{Hz})[/tex]

[tex]\boxed{E = 1.33 \times 10^{-14} \: \text{J}}[/tex]

Therefore, the energy of the photon is 1.33 × 10⁻¹⁴ J.

[tex]\\[/tex]

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