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write in standard form and find roots

1. 6/p - 2p/3 = 0

2. 8/n+2 + n-2/4 = 2


Sagot :

Answer:

1. p = { 3, -3)

2. n= { 2, 6}

Step-by-step explanation:

1. 6/p - 2p/3 = 0

multiply both sides by 3p

(6/p - 2p/3 = 0) x 3p

(6/p)(3p) - (2p/3)(3p) = (0)(3p)

(6)(3) - (2p)(p) = 0

18 - 2p^2 = 0

2p^2 = 18

divide both sides by 2

(2p^2)/2 = 18/2

p^2 = 9

√p^2 = √9

p = +/- 3

2. 8/n+2 + n-2/4 = 2

multiply both sides by 4(n+2)

(8/n+2 + n-2/4 = 2) x 4(n + 2)

(8)(4) + (n-2)(n+2) = 2x4(n+2)

32 + n^2 - 4 = 8(n+2)

32 + n^2 - 4 = 8n + 16

n^2 - 8n + 32 - 4 - 16 = 0

n^2 - 8n + 12 = 0

(n-6)(n - 2) = 0

n-6 = 0

n=6

n-2 = 0

n= 2