Question :
How many possible rational roots do the polynomial (x)=2׳-8ײ+2×-1 have??
Answer:
[tex] \huge \mathtt \orange{±1 ,±\frac{1}{2} }[/tex]
Step-by-step explanation:
[tex](x) - 2 {x}^{3} - 8 {x}^{2} + 2x - 1 \\ \\ (x) - 2 {x}^{3} + 8 {x}^{2} = 2x - 1 \\ \\ (x) - 2 {x}^{3} + 8 {x}^{2} - 2x = - 1 \\ \\ (x) = - 2 {x}^{3} + 8 {x}^{2} - 2x + 1 = 0 \\ \\ x = x - 2 {x}^{3} + 8 {x}^{2} - 2x + 1 = 0 \\ \\ x = x - 2 {x}^{3} + 8 {x}^{2} - x + 1 = 0 \\ \\ [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]x - 2 {x}^{3} + 8 {x}^{2} - x + 1 = 0 \\ \\ x - 2 {x}^{3} + 8 {x}^{2} - x + 1 \\ \\ - 2 {x}^{3} + 8 {x}^{2} + 0 + 1 \\ \\ - 2 {x}^{3} + 8 {x}^{2} + 1 \\ \\ [/tex]
- Kung ang polynomial function ay may integer coefficients, ang bawat rational zero ay magkakaroon ng form na pq kung saan ang p ay isang factor ng constant at q ay isang factor ng leading coefficient.
ANSWER :
[tex] \huge \mathtt \red{ = ±1,± \frac{1}{2} }[/tex]
hope its help
