Question:
Which of the following ordered pairs is a solution of the inequality 3x + 6y ≤ 20?
Proving:
A. (2, 1)
- 3x + 6y ≤ 20
- 3(2) + 6(1) ≤ 20
- 6 + 6 ≤ 20
- 12 ≤ 20
Is 12 less than or equal to 20? Yes, it is.
>>>>
B. (3, 2)
- 3x + 6y ≤ 20
- 3(3) + 6(2) ≤ 20
- 9 + 12 ≤ 20
- 21 ≤ 20
Is 21 greater than or equal to 20? No, it's not.
>>>>
C. (3, 3)
- 3x + 6y ≤ 20
- 3(3) + 6(3) ≤ 20
- 9 + 18 ≤ 20
- 27 ≤ 20
Is 27 less than or eual to 20? No, it's not.
>>>>
D. (0, 4)
- 3x + 6y ≤ 20
- 3(0) + 6(4) ≤ 20
- 0 + 24 ≤ 20
- 24 ≤ 20
Is 24 less than or equal to 20? No, it's not.
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