👤

N= 72,839, e = 11% given population and margin of error

Sagot :

Answer: Solutions

See all ›

Q:Question:

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 11) 90% confidence; n=300, x= 140 A) 0.0565 B) 0.0593 C) 0.0509 D) 0.0474 11)

Answer:

 Solution : Given that, n = 300 x = 140 Point est...

Q:Question:

Calculate the margin of error E = zalpha/2 . Sigma/n if the necessary requirements are satisfied. The confidence level is 90%, the sample size is n = 98, and sigma = 11. Are the necessary requirements satisfied? Use the given margin of error , confidence level and population standard deviation, sigma, to find the minimum sample size required to estimate an unknown population mean, mu. Margin of error : 0.8 inches, confidence level: 95%, sigma

A:Answer:

E = 1.645*11/sqrt(98) = 1.828   n = (Z * sigma / E...

Q:Question:

Question 11 (6.66 points) Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 2015, x = 1631 0.0145 0.0171 0.0192 0.0231

Q:Question:

estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 360, X = 49Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin

Brainly?