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Answered

Radium undergoes alpha decay. The product of this reaction also undergoes alpha
decay. What is the product of this second decay reaction?

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KizunaHighgo

[tex]\large \bold {SOLUTION}[/tex]

[tex]\small\boxed{\green{\sf{ {_{88}^{226}}Ra→{_{86}^{222}}Rn + \: _{2}^{4}He→{_{84}^{218}}Po + \: _{2}^{4}He}}}[/tex]

By α-decay, Radium-226 undergoes the deduction of precisely 4 atoms that are composed of 2 protons and neutrons each. Two α-decays will produce as a product of Polonium-218 plus the Helium atom that is released from the process.

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