The radius of a cone is decreasing at a constant rate of 1 inches per minute, and the volume is decreasing at a rate of 104 cubic inches per minute. At the instant when the height of the cone is 22 inches and the volume is 49 cubic inches, what is the rate of change of the height? The volume of a cone can be found with the equation V=\frac{1}{3}\pi r^2 h.V= 3 1 ​ πr 2 h. Round your answer to three decimal places