Sagot :
[tex]\large{\mathcal{SOLUTION:}}[/tex]
The perimeter of a triangle is the sum of the three sides.
- P = a + b + c
[tex] \\ [/tex]
Given:
- a = (3y²+4)cm
- b = (2y²-5x)cm
- c = (6x+2)cm
[tex] \\ [/tex]
Solving ,
- P = (3y²+4) + (2y²-5x) + (6x+2)
- P = 3y²+2y²-5x+6x+4+2
- P = 5y²+x+6
Therefore , the perimeter is (5y²+x+6)cm
[tex] \\ [/tex]
[tex]\large{\mathcal{ANSWER:}}[/tex]
- The perimeter is (5y²+x+6)cm
[tex] \\ [/tex]
[tex]\boxed{\begin{array}{} \blue{\text{DONT RELY ON CHANCES,}} \\ \red{\text{ WORK FOR THE HARDEST }} \\ \end{array}}[/tex]
[tex]\tt \green{QUESTION:}[/tex]
- The polynomials (3y² + 4) cm, (2y² - 5x) cm, and (6x + 2) cm represent the three sides of triangle. What is the perimeter of the triangle?
[tex]\red{\bold{ANSWER:}}[/tex]
- P= 5x²+x+6 cm is the Answer.
[tex]\red{\bold{SOLUTION}}[/tex]
- a=(3y²+4)
- a=(3y²+4)b= (2y²-5x)
- a=(3y²+4)b= (2y²-5x)c= (6x+2)
- a=(3y²+4)b= (2y²-5x)c= (6x+2)
- P=a+b+c
LINK:
https://brainly.ph/question/15405300
- KaiJoshua
HOPE THIS HELPS