Pakisagot po please need ko na po
Answer the given problem.
1. It costs a bakery Php 15 to make a loaf of bread and Php 30 to make a pineapple pie. Production
costs on these items cannot exceed Php 300. There must at least be 5 of these items.
a. Write a system of inequalities that shows the various combinations the bakery can produce these
two items. (Let x be the number of loaf bread and y be the number of pineapple pie.)
b. Graph.
c. Write 3 possible combinations of loaves of bread and pineapple pies.
Nonsense = report

Question

Leonardotheodore64go Leonardotheodore64go

Math

Answered

Pakisagot po please need ko na po
Answer the given problem.
1. It costs a bakery Php 15 to make a loaf of bread and Php 30 to make a pineapple pie. Production
costs on these items cannot exceed Php 300. There must at least be 5 of these items.
a. Write a system of inequalities that shows the various combinations the bakery can produce these
two items. (Let x be the number of loaf bread and y be the number of pineapple pie.)
b. Graph.
c. Write 3 possible combinations of loaves of bread and pineapple pies.
Nonsense = report

Sagot :

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MasterZefiago MasterZefiago · Answer 1

Let:

x = number of loaves of bread.

y = number of pineapple pies.

your equations are:

x + y >= 15

15x + 30y <= 300

x >= 0

y >= 0

the first equation is the number of items that are to be produced.

the second equation is the cost for producing these items.

using the desmos.com graphing software, you will graph the opposite of these inequalities.

the area of the graph that is not shaded will be the region of feasibility.

the corner points of this graph shows the minimum cost solution.

you don't need that, but the graphing solution does provide it, if needed.

i chose 5 points.

you can pick any one of those that you like.

3 of the points are at the corners of the feasible region (the unshaded portion of the graph).

2 of the points are within the feasible region (not at the corner points).

the points at the corner are:

(10,5)

(15,0)

(20,0)

it is at these points that the maximum or minimum value solution will lie.

the points not at the corner are:

(14,2)

(16,1)

the points are in (x,y) format.

all the constraints need to be satisfied at each of these points.

x + y >= 15 is satisfied at all these points.

15x + 30y <= 300 is also satisfied at all these points.

all points have x >= 0 and y >= 0.

to demonstrate how to find the minimum cost solution, you would evaluate the cost at each of the corner points.

(10,5) yields a total cost of 10*15 + 5*30 = 300

(15,0) yields a total cost of 15*15 = 225

(20,0) yields a total cost of 20*15 = 300

we will also evaluate the cost at each of the points not at the corners to demonstrate that the minimum cost lies at the corner points.

(14,2) = 14*15 + 2*30 = 270

(16,1) = 16*15 + 1*30 = 270

the minimum cost is at (15,0) which is at one of the corner points.

you can try any of the other points within the feasible region and you will find that none of them will give you a cost less than 225.

Step-by-step explanation:

I’ll send the picture for the graph. (I can’t download the picture so I decided to screenshot it. I’m sorry if medyo blurred siya.)

Kindly read it carefully.

Answer by Theo (11793) So credits to him/her. (Permission to copy your answer sir/ma’am Theo)

Source: Algebra

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