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1. The speed of light in ethyl alcohol is 2.2 x 10 8 m/s. Find its index of refraction if the speed of light in a vacuum is 3 x 108 m/s.​

Sagot :

Index of Refraction

To determine the index of refraction, we will use the formula:

[tex]n = \frac{c}{v} [/tex]

where:

n = the index of refraction

c = the speed of light in vacuum

v = the speed of light in material

Answer

1.

Given

c = 3 x 10⁸ m/s

v = 2.2 x 10⁸ m/s

n = ?

Solve

[tex]n = \frac{c}{v} \\ n = \frac{3 \times {10}^{8}\:m/s}{2.2 \times {10}^{8}\:m/s} \\ n = 1.4 \times {10}^{8}\:m/s[/tex]

∴ The index of refraction is 1.4 x 10⁸ m/s.