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f varies jointly as g and h.if f=15 when g=3and h =1, find f when g =6and h=9?

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AGboiigo

[tex]\large{\mathcal{SOLUTION:}}[/tex]

Equation: f = kgh

[tex] \\ [/tex]

Given: f = 15 , g = 3 , h = 1

STEP 1: Find for the constant k

  • f = kgh
  • 15 = k(3)(1)
  • 15 = 3k
  • 15/3 = k
  • 5 = k

[tex] \\ [/tex]

Given: f = ? , g = 6 , h = 9 , k = 5

STEP 2: Find for the unknown

  • f = kgh
  • f = 5(6)(9)
  • f = 270

Therefore , the value of f is 270

[tex] \\ [/tex]

[tex]\large{\mathcal{ANSWER:}}[/tex]

  • f = 270

[tex] \\ [/tex]

JuniorZxgo

✒️[tex]\large \bold{QUESTION} [/tex]

F varies jointly as g and h. If f = 15 when g = 3 and h = 1, find f when g = 6 and h = 9?

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✒️[tex]\large \bold{ANSWER} [/tex]

  • F = 270

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✒️[tex]\large \bold{SOLUTION} [/tex]

Step 1 : Formulate

Based on the given conditions formulate

f = kgh

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Step 2 : Subtitute

  • f = 15
  • g = 3
  • h = 1
  • into f = kgh:

15 = k × 3

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Step 3 : Solve the Equation

15 = k × 3

k × 3 = 15

[tex]k = \frac{15}{3} [/tex]

k = 5

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Step 4 : Find the Function

Find the equation of the function.

  • f = 5gh

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Step 5 : Subtitute

  • Subtitute g = 6 into f = 5gh

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Step 6 : Solve the Equation

  • f = 5 × 6 × 9
  • f = (5 × 6) × 9
  • f = 30 × 9
  • = 270

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  • So the Correct Answer is 270

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