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of y varies directly as x. if y = 8 when x = 2, find y when x = 5

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MissJindySummergo

Question:

y varies directly as x. if y = 8 when x = 2, find y when x = 5

[tex]\underline{\mathbb{REMEMBER:}}[/tex]

  • Direct variation: y = kx

[tex]\boxed{\tt{Solution:}}[/tex]

  • y = 8, x = 2
  • y = kx
  • 8 = k · 2
  • 8/2 = k
  • 4 = k

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  • y = ?, x = 5, k = 4
  • y =  kx
  • y = 4 · 5
  • y = 20

[tex]\huge\boxed{\tt{ANSWER:}}[/tex]

  • The value of y is 20.
AGboiigo

[tex]\large{\mathcal{SOLUTION:}}[/tex]

Equation: y = kx

[tex] \\ [/tex]

Given: y = 8 , x = 2

STEP 1: Find for the constant k

  • y = kx
  • 8 = k(2)
  • 8/2 = k
  • 4 = k

STEP 2: Find for the unknown

Given: y = ? , x = 5 , k = 4

  • y = kx
  • y = (4)(5)
  • y = 20

Therefore , the value of y is 20 when x is 5

[tex] \\ [/tex]

[tex]\large{\mathcal{ANSWER:}}[/tex]

  • y = 20

[tex] \\ [/tex]

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