For questions no. 27-29
Solve the given Partitive Proportion
(Let 2 be the first term while the 5 is the second term and 6 as the third term)
2N + 5N + 6N = 416
(Find the value of N)
13N/13 = 416/13
(Divide both side by 13)
N = 32
(Now we substitute the value of N which is 32)
2(32) + 5(32) + 6(32) = 416
(Multiply each term beacuse we already substitute the value of N)
64 + 160 + 192 = 416
(Now, we find the product of each term and that is the numbers)
416 = 416
(Therefore, the answer is correct because the sum of the three numbers are equal to the sum of the ratio)
27) The first number is 64
28) The second number is 160
29) The third number is 192
For question no. 30
Solve for Inverse/Indirect Proportion
4/N = 2/5
(Rename the given numbers as a fraction)
(N) (2) = (4) (5)
(Do the cross multiplication in the fraction)
2N/2 = 20/2
(Divide both side by 2)
N = 10
(Therefore, the value of N is 10)
30) There will be 10 teachers
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{See the attached images for the solutions and other example of Partitive Proportion and Inverse Proportion}
