Learning Task 2 :Find the area of the
Standard region. Use = 3.14.
![Learning Task 2 Find The Area Of The Standard Region Use 314 class=](https://ph-static.z-dn.net/files/d23/ac32e3a517a4233d21e549b3d72275cf.jpg)
Answer:
AREA OF CIRCLE
\mathbb{PROBLEM:}PROBLEM:
Learning Task 2: In your answer sheet, copy and find the area of the shaded region.
\mathbb{SOLUTION:}SOLUTION:
»Find The Diameter
\bold{diameter} = 2rdiameter=2r
d = 2 \times \green{9}d=2×9
\boxed{d = \green{18} }
d=18
»Find The Circumferance
\bold{circumferance} = 2\pi \orange{r}circumferance=2πr
c = 2 \times \pi \times \green{9}c=2×π×9
c = 18 \green{\pi}c=18π
c = 56. \green{54}c=56.54
»Find The Area
\bold{area} = \pi \orange{r}^{2}area=πr
2
a = \pi \times {9}^{2}a=π×9
2
a = 81\pia=81π
a = 254. \green{469005}a=254.469005
So the are is \boxed{a = 254. \green{469005} \: in \: ^{2} }
a=254.469005in
2
#CarryOnLearning
diko lang po sure .. hehe