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Activity 2. Solve for the unknown.
1. If x varies jointly as y and z and x = 12 when y = 1 and z= 6, find x when y=6 and z = 10.

2. If z varies jointly as x and y and if z = 1 when y = 2 and x = -3, find x when z = 2 and y = 4

3. If x varies directly as y and inversely as z, and if x = 30 when y = 2 and z= 3, find y=z=15 and x = 30.

pasagot ng maayos​


Sagot :

Answer:

Answer:

1. x = 120

2. x = -3

3. y = 10

Step-by-step explanation:

1. x varies jointly as y and z

x = kyz where k is the constant of variation

if x = 12, y = 1 and z = 6

x = kyz

12 = k ( 1 ) ( 6 )

12 = k ( 6 )

k = 12/6

k = 2

find x if y = 6 and z = 10.

x = kyz

x = ( 2 ) ( 6 ) ( 10 )

x = ( 12 ) ( 10 )

x = 120

2. z varies jointly as x and y

z = kxy where k is the constant of variation

if z = I, y = 2 and x = -3

z = kxy

( 1 ) = k ( -3 ) ( 2 )

1 = k ( -6 )

k = 1/( -6 )

k = -1/6

find x if z = 2 and y = 4

z = kxy

( 2 ) = ( -1/6 ) ( x ) ( 4 )

2 = x ( -4/6 )

2 = x ( -2/3 )

x = 2/( -2/3 )

x = 2 * ( -3/2 )

x = -6/2

x = -3

3. x varies directly as y and inversely as z

x = ky/z where k is the constant of variation

if x = 30, y = 2 and z = 3

x = ky/z

( 30 ) = k ( 2 )/( 3 )

30 = k ( 2 )/3

( 30 ) ( 3 ) = k ( 2 )

k ( 2 ) = 90

k = 90/2

k = 45

find y if z = 15 and x = 30.

x = ky/z

( 30 ) = ( 45 ) y/( 15 )

30 = 3 ( y )

y = 30/3

y = 10