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evaluate the algebraic expression6(y-4)+(y+1)² when y=2.​

Sagot :

Answer:

-3

Step-by-step explanation:

6(y-4)+(y+1)²

y=2

then,  

6(2 - 4) + (2+1)²

6(-2) + (3)²

-12 + 9

-3

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Evaluate the algebraic expression 6(y-4)+(y+1)² when y=2.

SOLUTION :

[tex]\rm \: putting \:\: y = 2 \: \: in \: \: 6(y - 4) + (y + 1) {}^{2} \\ \rm \: we \: set \: , \: 6(2 - 4) + (2 + 1) {}^{2} \\ \rm = 6( - 2) + 3 {}^{2} \\ \rm = - 12 + 9 \\ \rm = \: - 3[/tex]

ANSWER :

  • -3

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