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The length of a rectangle is 4 feet less than twice its width. The perimeter is 112 meters. Find the dimensions of the rectangle.

Sagot :

Answer:

20 feet and 36 feet

Step-by-step explanation:

Given:

  • Length = 2x - 4
  • Width = x
  • P = 112 meters

We plug the values to the perimeter formula of rectangle and find for the value of x

  • P = 2(L+W)
  • 112 = 2(2x-4 + x)
  • 112 = 2(3x-4)
  • 112 = 6x-8
  • 112+8 = 6x
  • 120 = 6x
  • 120/6 = x
  • 20 = x

Then , we substitute the value of x to the dimensions

  • Length = 2x-4
  • Length = 2(20) - 4
  • Length = 40-4
  • Length = 36

  • Width = x
  • Width = 20

Therefore , the dimensions are 20 feet and 36 feet