Answer
Letter A.
1. 2x³
2. [tex]16a^{6}[/tex]
Letter B.
1. 12r² - 4r - 5
2. [tex]x + 6[/tex]
Solution
Letter A.
1.
= (2x) (x²)
= 2x³
2.
= (4a³)²
= [tex]4^{2}a^{3x2}[/tex]
= [tex]16a^{6}[/tex]
Letter B.
1.
= (6r - 5) (2r + 1)
= 12r² + 6r - 10r - 5
= 12r² - 4r - 5
2.
= [tex]\frac{x^{2} + 2x - 24}{x-4}[/tex]
= [tex]\frac{(x+6)(x-4)}{x-4}[/tex]
= [tex]\frac{x+6}{1}[/tex]
= [tex]x + 6[/tex]
