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Answered

find the equation of a line parallel to the line 4x-y+8=0 passing at distance (-2,-4)

Sagot :

AGboiigo

Answer:

4x-y+4 = 0

Step-by-step explanation:

Parallel = same slope

Given:

  • 4x-y+8 = 0

So , the other equation will be

  • 4x-y+C = 0

Now to find the value of C , we will substitute the point (-2,-4)

  • 4x-y+C = 0
  • 4(-2)-(-4)+C = 0
  • -8+4+C = 0
  • -4+C = 0
  • C = 4

Hence , the equation will be 4x-y+4 = 0

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