1) (x² - 3x - 9) ÷ (x - 1)
[tex] \frac{(x ^ 2 - 3x - 9)}{(x - 1)} \\ = \frac{ {x}^{2} - 3x - 9}{x - 1} \\ = x + \frac{-2x-9}{x - 1} \\ = x - 2 + \frac{-11}{x - 1} \\ = x - 2 - \frac{ - 11}{x - 1} [/tex]
2) (2x² + 4x - 7) ÷ (x - 2)
[tex]\frac{(2x^ 2+ 4x-7)}{(x - 2)} \\ = \frac{2x^ 2+ 4x-7}{x - 2} \\ = 2x + \frac{8x7}{x - 2} \\ = 2x+8+ \frac{9}{x - 2} [/tex]
