✒️ MATHEMATICS
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[tex]\large\underline\bold{SOLUTION:}[/tex]
» E varies jointly as half of A and R and varies inversely as T and H, expressed as:
Where, K = constant of variation
» If E = 49.5 , A = 9 , K = 6 , T = 3 and H = 2, Solve for K
- 49.5 = 1/2 k(9)(6) / (3)(2)
- 49.5(2)(3)(2) = 54k
- 594 = 54k
- k = 594/54
- k = 11
» If k = 11, E = 33, A = 18, R = 5, T = 3, Value of H is:
- 33 = 1/2 (11)(18)(5) / (3)(H)
- 33(2)(3)(H) = (11)(18)(5)
- 198H = 990
- H = 990/198
- H = [tex]{\boxed{\green{\sf{5 }}}}[/tex]
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[tex]\large\underline\bold{ANSWER:}[/tex]
- Therefore, H = 5 when E = 33, A = 18, R = 5, and T = 3.
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hope this helps
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